Question

a metal block with a mass of 55.0 g. was heated from 16.4 c to 46.4 c. the specific heat of the metal is 0.978 j/gc. how many joules of energy was absorbed by this metal block? question 2 1 pts water was heated using a hot plate. the initial temperature of the water was 25.74 c and the final temperature was 73.3 c. what are the deltat for this (change in temperature)?

Explanation:

Step1: Calculate the energy absorbed by the metal block

Use the formula \(Q = mc\Delta T\), where \(m = 55.0\space g\), \(c=0.978\space J/g^{\circ}C\), and \(\Delta T=T_{final}-T_{initial}=46.4 - 16.4=30.0^{\circ}C\)

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Step2: Calculate the value of \(Q\)

\(1650\times0.978 = 1613.7\space J\)

Step3: Calculate \(\Delta T\) for water

Use the formula \(\Delta T=T_{final}-T_{initial}\), where \(T_{final} = 73.3^{\circ}C\) and \(T_{initial}=25.74^{\circ}C\)
\(\Delta T=73.3 - 25.74=47.56^{\circ}C\)

Answer:

The energy absorbed by the metal block is \(1613.7\space J\). The \(\Delta T\) for water is \(47.56^{\circ}C\)