Question

measurements have shown that the concentration of salt in seawater is 35.5 g l^{-1}. calculate the volume in liters of seawater that must be evaporated to recover 875. g of salt.
be sure your answer has the correct number of significant digits.

Explanation:

Step1: Recall the formula for concentration

Concentration \(C=\frac{m}{V}\), where \(C\) is concentration, \(m\) is mass, and \(V\) is volume. We can rearrange it to solve for \(V\): \(V = \frac{m}{C}\).

Step2: Substitute the given values

Given \(m = 875\space g\) and \(C=35.5\space g/L\). Then \(V=\frac{875\space g}{35.5\space g/L}\).

Step3: Calculate the value

\(V=\frac{875}{35.5}\approx24.6479\space L\).

Answer:

\(24.6\space L\) (rounded to three significant digits as \(875\) has three significant digits and \(35.5\) has three significant digits)