Question

magnesium (24.30 g) reacts with hydrogen chloride (x g) to produce hydrogen gas (2.04 g) and magnesium chloride (96.90 g). what mass of hydrogen chloride was used in the reaction?______ g hclround your answer to the second decimal.

Explanation:

Step1: Apply the law of conservation of mass

According to the law of conservation of mass, the mass of reactants is equal to the mass of products. So, \(m(\text{Mg})+m(\text{HCl}) = m(\text{H}_2)+m(\text{MgCl}_2)\)

Step2: Rearrange the formula to solve for \(m(\text{HCl})\)

\(m(\text{HCl})=m(\text{H}_2)+m(\text{MgCl}_2)-m(\text{Mg})\)

Step3: Substitute the given values

Substitute \(m(\text{Mg}) = 24.30\space g\), \(m(\text{H}_2)=2.04\space g\), and \(m(\text{MgCl}_2) = 96.90\space g\) into the formula:
\(m(\text{HCl})=2.04 + 96.90-24.30\)
\(m(\text{HCl})=74.64\space g\)

Answer:

\(74.64\)