Question

lab 2: mass and volume lab
in the \mass and volume lab\ we used water displacement to measure volume of some samples. a student
decided to directly measure the density of aluminum using a balance and water displacement. the student
data is provided below:

1. calculate the density of the aluminum foil using the students data provided. show the numerical setup

and calculated result. 1

1. calculate the percent error of the students density. the accepted value is 2.70g/ml. show the

mathematical representation and calculated result. 1

Explanation:

Step1: Calculate the density of aluminum foil

The formula for density is \(d=\frac{m}{V}\). The volume \(V\) of the aluminum foil is the final volume minus the initial volume. So \(V = 11.65\space mL- 10.00\space mL=1.65\space mL\), and the mass \(m = 4.23\space g\). Then \(d=\frac{4.23\space g}{1.65\space mL}\approx2.56\space g/mL\)

Step2: Calculate the percent error

The formula for percent error is \(\text{Percent Error}=\frac{\vert\text{Experimental Value}-\text{Accepted Value}\vert}{\text{Accepted Value}}\times100\%\). The experimental value \(d_{exp}=2.56\space g/mL\) and the accepted value \(d_{acc} = 2.70\space g/mL\). So \(\text{Percent Error}=\frac{\vert2.56 - 2.70\vert}{2.70}\times100\%=\frac{0.14}{2.70}\times 100\%\approx5.19\%\)

Answer:

The density of the aluminum foil is approximately \(2.56\space g/mL\) and the percent error is approximately \(5.19\%\)