Question

lab data
reactants
appearance of
reactants
observations after mixing
(select all that apply)
products
(select all that apply)
naoh(aq) + cuso4(aq)
the tub just change
it color to a dark
blue there was no
reaction between
the chemicals.
no observable change
bubbles formed in mixture
mixtures color changed
solid formed in mixture
test tube felt colder
test tube felt hotter
no reaction occurred
cu2oh(s)
cu(oh)2(aq)
cuoh(s)
cu(oh)2(s)
na2so4(aq)
naso4(aq)
naso4(s)
nacl(aq) + pb(no3)2(aq)
there was no
change in the
chemicals the was
no reaction to the
chemicals and they
did not mix.
no observable change
bubbles formed in mixture
mixtures color changed
solid formed in mixture
test tube felt colder
test tube felt hotter
no reaction occurred
pbcl2(aq)
pbcl2(s)
pbcl(s)
pb2cl(s)
nano3(aq)
nano3(s)
na2no3(aq)
na(no3)2(s)
bacl2(aq) + h2so4(aq)
the chemical did
not mix together the
sulfuric acid sank in
to the barium
chloride.
no observable change
bubbles formed in mixture
mixtures color changed
solid formed in mixture
test tube felt colder
test tube felt hotter
no reaction occurred
baso4(s)
baso4(aq)
ba(so4)2(s)
ba2so4(aq)
hcl2(aq)
hcl(aq)
h2cl(aq)
hcl(s)
mgso4(aq) + ni(no3)2(aq)
the tube is a room
tempter no chemical
reaction and a light
shade of green.
no observable change
bubbles formed in mixture
mixtures color changed
solid formed in mixture
test tube felt colder
test tube felt hotter
no reaction occurred
mgno3(aq)
mg(no3)2(s)
mg2no3(s)
mgno3(aq)
ni2so4(aq)
niso4(s)
ni(so4)2(s)

Explanation:

Step1: Analyze the reaction \(NaOH(aq)+CuSO_{4}(aq)\)

The chemical reaction is \(2NaOH(aq)+CuSO_{4}(aq)=Cu(OH)_{2}(s)+Na_{2}SO_{4}(aq)\). A solid (\(Cu(OH)_{2}\)) is formed, so the observation "Solid formed in mixture" is correct, and the products are \(Cu(OH)_{2}(s)\) and \(Na_{2}SO_{4}(aq)\)

Step2: Analyze the reaction \(NaCl(aq)+Pb(NO_{3})_{2}(aq)\)

The reaction is \(2NaCl(aq)+Pb(NO_{3})_{2}(aq)=PbCl_{2}(s)+2NaNO_{3}(aq)\). A solid (\(PbCl_{2}\)) is formed, so the observation "Solid formed in mixture" is correct, and the products are \(PbCl_{2}(s)\) and \(NaNO_{3}(aq)\)

Step3: Analyze the reaction \(BaCl_{2}(aq)+H_{2}SO_{4}(aq)\)

The reaction is \(BaCl_{2}(aq)+H_{2}SO_{4}(aq)=BaSO_{4}(s)+2HCl(aq)\). A solid (\(BaSO_{4}\)) is formed, so the observation "Solid formed in mixture" is correct, and the product is \(BaSO_{4}(s)\)

Step4: Analyze the reaction \(MgSO_{4}(aq)+Ni(NO_{3})_{2}(aq)\)

According to the solubility rules, \(MgSO_{4}(aq)\) and \(Ni(NO_{3})_{2}(aq)\) do not react. So the observation "No observable change" is correct, and the product is "No reaction occurred"

Answer:

For \(NaOH(aq)+CuSO_{4}(aq)\): Observation - Solid formed in mixture; Products - \(Cu(OH)_{2}(s)\), \(Na_{2}SO_{4}(aq)\)
For \(NaCl(aq)+Pb(NO_{3})_{2}(aq)\): Observation - Solid formed in mixture; Products - \(PbCl_{2}(s)\), \(NaNO_{3}(aq)\)
For \(BaCl_{2}(aq)+H_{2}SO_{4}(aq)\): Observation - Solid formed in mixture; Products - \(BaSO_{4}(s)\)
For \(MgSO_{4}(aq)+Ni(NO_{3})_{2}(aq)\): Observation - No observable change; Products - No reaction occurred