Question

in the isosceles trapezoid below,
$x = ?^{circ}$
$5x + 15^{circ}$
$7x - 11^{circ}$

Explanation:

Step1: Set up the equation

In an isosceles trapezoid, base angles are equal. So, \(5x + 15=7x - 11\).

Step2: Solve for \(x\)

Subtract \(5x\) from both sides: \(15 = 2x-11\).
Add \(11\) to both sides: \(26 = 2x\).
Divide both sides by \(2\): \(x = 13\).

Answer:

\(13\)