Question

in the isosceles trapezoid below, $x = ?^{circ}$ $5x - 20^{circ}$ $2x + 37^{circ}$

Explanation:

Step1: Use property of isosceles trapezoid

In an isosceles trapezoid, base - angles are equal. So, we set up the equation $5x - 20=2x + 37$.

Step2: Isolate the variable terms

Subtract $2x$ from both sides of the equation: $5x-2x - 20=2x-2x + 37$, which simplifies to $3x-20 = 37$.

Step3: Isolate the variable

Add 20 to both sides: $3x-20 + 20=37 + 20$, getting $3x=57$.

Step4: Solve for x

Divide both sides by 3: $x=\frac{57}{3}$.

Answer:

$x = 19$