Question

iron reacts with sulfur to form iron sulfide. if 60 grams of iron reacts with sulfur to produce 90 grams of iron sulfide, how much sulfur has been used in the chemical reaction?
oa. 30 grams
ob. 120 grams
oc. 60 grams
od. 150 grams

Explanation:

Step1: Apply the law of conservation of mass

The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. Let the mass of sulfur be \(m\). The mass of iron (\(m_{Fe} = 60\space g\)) and the mass of sulfur (\(m\)) react to form iron sulfide (\(m_{FeS}=90\space g\)). So, \(m_{Fe}+m = m_{FeS}\).

Step2: Solve for the mass of sulfur

Rearrange the equation \(m = m_{FeS}-m_{Fe}\). Substitute \(m_{Fe}=60\space g\) and \(m_{FeS} = 90\space g\) into the equation. Then \(m=90 - 60\).

Answer:

A. 30 grams