ionic compounds
if given the formula, give the name and vice versa:
a) cal₂
calcium iodide
b) lead (ii) perchlorate
c) zinc nitride
d) cus
e) copper (ii) nitrate
f) calcium fluoride
g) copper (ii) bromide
h) (nh₄)₂so₃
i) sr₃(po₄)₂
j) nh₄cl
k) titanium (iv) nitride
l) cu₂o
m) mg(oh)₂
n) na₂so₄
o) copper (i) nitride
p) rabr₂
q) magnesium sulphide
r) mnbr₃
s) aluminum nitrate
t) ammonium sulphate
u) sodium oxide
v) na₂o
w) tin (iv) sulphide
x) cuo
y) zinc hydrogen sulphate
z) fe₂(so₄)₃

Question

Accepted Answer

### Part (b)
# Explanation:
## Step1: Identify ions
Lead (II) has charge $ \text{Pb}^{2+} $, perchlorate is $ \text{ClO}_4^- $.
## Step2: Balance charges
To balance $ 2+ $ and $ 1- $, we need 2 perchlorate ions. So formula is $ \text{Pb(ClO}_4\text{)}_2 $.
# Answer: $ \text{Pb(ClO}_4\text{)}_2 $

### Part (c)
# Explanation:
## Step1: Identify ions
Zinc has charge $ \text{Zn}^{2+} $, nitride is $ \text{N}^{3-} $.
## Step2: Find LCM of charges (6)
Zinc: $ \frac{6}{2} = 3 $, Nitride: $ \frac{6}{3} = 2 $. So formula is $ \text{Zn}_3\text{N}_2 $.
# Answer: $ \text{Zn}_3\text{N}_2 $

### Part (d)
# Explanation:
## Step1: Identify ions
Copper (from CuS, assume Cu²⁺ as S is $ \text{S}^{2-} $), sulfide is $ \text{S}^{2-} $.
## Step2: Balance charges
$ 2+ $ and $ 2- $ balance, so name is Copper (II) Sulfide.
# Answer: Copper (II) Sulfide

### Part (e)
# Explanation:
## Step1: Identify ions
Copper (II) is $ \text{Cu}^{2+} $, nitrate is $ \text{NO}_3^- $.
## Step2: Balance charges
2 nitrate ions for 1 copper (II). Formula: $ \text{Cu(NO}_3\text{)}_2 $.
# Answer: $ \text{Cu(NO}_3\text{)}_2 $

### Part (f)
# Explanation:
## Step1: Identify ions
Calcium is $ \text{Ca}^{2+} $, fluoride is $ \text{F}^- $.
## Step2: Balance charges
2 fluoride ions for 1 calcium. Formula: $ \text{CaF}_2 $.
# Answer: $ \text{CaF}_2 $

### Part (g)
# Explanation:
## Step1: Identify ions
Copper (II) is $ \text{Cu}^{2+} $, bromide is $ \text{Br}^- $.
## Step2: Balance charges
2 bromide ions for 1 copper (II). Formula: $ \text{CuBr}_2 $.
# Answer: $ \text{CuBr}_2 $

### Part (h)
# Explanation:
## Step1: Identify ions
Ammonium is $ \text{NH}_4^+ $, sulfite is $ \text{SO}_3^{2-} $.
## Step2: Balance charges
2 ammonium ions for 1 sulfite. Name: Ammonium Sulfite.
# Answer: Ammonium Sulfite

### Part (i)
# Explanation:
## Step1: Identify ions
Strontium is $ \text{Sr}^{2+} $, phosphate is $ \text{PO}_4^{3-} $.
## Step2: Find LCM (6)
Strontium: $ \frac{6}{2}=3 $, Phosphate: $ \frac{6}{3}=2 $. Formula: $ \text{Sr}_3(\text{PO}_4)_2 $ (name is Strontium Phosphate).
# Answer: Strontium Phosphate

### Part (j)
# Explanation:
## Step1: Identify ions
Ammonium $ \text{NH}_4^+ $, chloride $ \text{Cl}^- $.
## Step2: Balance charges
1:1 ratio. Name: Ammonium Chloride.
# Answer: Ammonium Chloride

### Part (k)
# Explanation:
## Step1: Identify ions
Titanium (IV) $ \text{Ti}^{4+} $, nitride $ \text{N}^{3-} $.
## Step2: LCM (12)
Titanium: $ \frac{12}{4}=3 $, Nitride: $ \frac{12}{3}=4 $. Formula: $ \text{Ti}_3\text{N}_4 $.
# Answer: $ \text{Ti}_3\text{N}_4 $

### Part (l)
# Explanation:
## Step1: Identify ions
Copper (I) $ \text{Cu}^+ $, oxide $ \text{O}^{2-} $.
## Step2: Balance charges
2 copper (I) for 1 oxide. Name: Copper (I) Oxide.
# Answer: Copper (I) Oxide

### Part (m)
# Explanation:
## Step1: Identify ions
Magnesium $ \text{Mg}^{2+} $, hydroxide $ \text{OH}^- $.
## Step2: Balance charges
2 hydroxide ions for 1 magnesium. Formula: $ \text{Mg(OH)}_2 $ (name is Magnesium Hydroxide).
# Answer: Magnesium Hydroxide

### Part (n)
# Explanation:
## Step1: Identify ions
Sodium $ \text{Na}^+ $, sulfate $ \text{SO}_4^{2-} $.
## Step2: Balance charges
2 sodium ions for 1 sulfate. Formula: $ \text{Na}_2\text{SO}_4 $ (name is Sodium Sulfate).
# Answer: Sodium Sulfate

### Part (o)
# Explanation:
## Step1: Identify ions
Copper (I) $ \text{Cu}^+ $, nitride $ \text{N}^{3-} $.
## Step2: LCM (3)
Copper: $ \frac{3}{1}=3 $, Nitride: $ \frac{3}{3}=1 $. Formula: $ \text{Cu}_3\text{N} $.
# Answer: $ \text{Cu}_3\text{N} $

### Part (p)
# Explanation:
## Step1: Identify ions
Radium $ \text{Ra}^{2+} $, bromide $ \text{Br}^- $.
## Step2: Balance charges
2 bromide ions for 1 radium. Formula: $ \text{RaBr}_2 $ (name is Radium Bromide).
# Answer: Radium Bromide

### Part (q)
# Explanation:
## Step1: Identify ions
Magnesium $ \text{Mg}^{2+} $, sulfide $ \text{S}^{2-} $.
## Step2: Balance charges
1:1 ratio. Formula: $ \text{MgS} $.
# Answer: $ \text{MgS} $

### Part (r)
# Explanation:
## Step1: Identify ions
Manganese (from $ \text{MnBr}_3 $, charge $ \text{Mn}^{3+} $), bromide $ \text{Br}^- $.
## Step2: Balance charges
3 bromide ions for 1 manganese (III). Name: Manganese (III) Bromide.
# Answer: Manganese (III) Bromide

### Part (s)
# Explanation:
## Step1: Identify ions
Aluminum $ \text{Al}^{3+} $, nitrate $ \text{NO}_3^- $.
## Step2: Balance charges
3 nitrate ions for 1 aluminum. Formula: $ \text{Al(NO}_3\text{)}_3 $.
# Answer: $ \text{Al(NO}_3\text{)}_3 $

### Part (t)
# Explanation:
## Step1: Identify ions
Ammonium $ \text{NH}_4^+ $, sulfate $ \text{SO}_4^{2-} $.
## Step2: Balance charges
2 ammonium ions for 1 sulfate. Formula: $ (\text{NH}_4)_2\text{SO}_4 $.
# Answer: $ (\text{NH}_4)_2\text{SO}_4 $

### Part (u)
# Explanation:
## Step1: Identify ions
Sodium $ \text{Na}^+ $, oxide $ \text{O}^{2-} $.
## Step2: Balance charges
2 sodium ions for 1 oxide. Formula: $ \text{Na}_2\text{O} $.
# Answer: $ \text{Na}_2\text{O} $

### Part (v)
# Explanation:
## Step1: Identify ions
Sodium $ \text{Na}^+ $, oxide $ \text{O}^{2-} $.
## Step2: Balance charges
2 sodium ions for 1 oxide. Name: Sodium Oxide.
# Answer: Sodium Oxide

### Part (w)
# Explanation:
## Step1: Identify ions
Tin (IV) $ \text{Sn}^{4+} $, sulfide $ \text{S}^{2-} $.
## Step2: Balance charges
2 sulfide ions for 1 tin (IV). Formula: $ \text{SnS}_2 $.
# Answer: $ \text{SnS}_2 $

### Part (x)
# Explanation:
## Step1: Identify ions
Copper (II) $ \text{Cu}^{2+} $, oxide $ \text{O}^{2-} $.
## Step2: Balance charges
1:1 ratio. Name: Copper (II) Oxide.
# Answer: Copper (II) Oxide

### Part (y)
# Explanation:
## Step1: Identify ions
Zinc $ \text{Zn}^{2+} $, hydrogen sulfate $ \text{HSO}_4^- $.
## Step2: Balance charges
2 hydrogen sulfate ions for 1 zinc. Formula: $ \text{Zn(HSO}_4\text{)}_2 $.
# Answer: $ \text{Zn(HSO}_4\text{)}_2 $

### Part (z)
# Explanation:
## Step1: Identify ions
Iron (III) $ \text{Fe}^{3+} $, sulfate $ \text{SO}_4^{2-} $.
## Step2: LCM (6)
Iron: $ \frac{6}{3}=2 $, Sulfate: $ \frac{6}{2}=3 $. Formula: $ \text{Fe}_2(\text{SO}_4)_3 $ (name is Iron (III) Sulfate).
# Answer: Iron (III) Sulfate

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QUESTION IMAGE

Question

Explanation:

Part (b)

Step1: Identify ions

Step2: Balance charges

Step1: Identify ions

Step2: Find LCM of charges (6)

Step1: Identify ions

Step2: Balance charges

Answer:

Part (c)