Question

iodine has an electron configuration of

• ( 1 s ^ { 2 } 2 s ^ { 2 } 2 p ^ { 6 } 3 s ^ { 2 } 3 p ^ { 6 } 4 s ^ { 2 } 3 d ^ { 10 } 4 p ^ { 6 } 5 s ^ { 2 } 4 d ^ { 10 } 5 p ^ { 5 } )

which of the following would also have an electron configuration ending in ( p ^ { 5 } )?
br
te
xe

Explanation:

Elements in the same group (column) of the periodic table have similar electron configurations. Iodine (I) is in group 17 (halogens). Bromine (Br) is also in group 17. The electron configuration of Br is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{5}\), which ends in \(p^{5}\). Tellurium (Te) is in group 16 (electron configuration ends in \(p^{4}\)) and Xenon (Xe) is in group 18 (electron configuration ends in \(p^{6}\)).

Answer:

Br