Question

interpreting the question
the given is 5.0 mol nal and the unknown is mol i2.
the ratio needed to change from nal to i2 is:
2.0 mol nal / 1 mol i2.
the balanced equation is:
br2 + 2nal → i2 + 2nabr
how many moles of i2 form during the reaction?
0.40 mol i2
2.5 mol i2

1. mol i2

Explanation:

Step1: Analyze the mole ratio

From the balanced equation \(Br_2 + 2NaI
ightarrow I_2 + 2NaBr\), the mole ratio of \(NaI\) to \(I_2\) is \(2:1\).

Step2: Calculate the moles of \(I_2\)

Given \(n(NaI)=5.0\space mol\). Using the mole - ratio \(\frac{n(I_2)}{n(NaI)}=\frac{1}{2}\), then \(n(I_2)=\frac{1}{2}\times n(NaI)\). Substitute \(n(NaI) = 5.0\space mol\) into the formula: \(n(I_2)=\frac{1}{2}\times5.0\space mol = 2.5\space mol\)

Answer:

\(2.5\space mol\space I_2\)