Question

ice cube (27.5g) is at -8.0°c. how much energy is required to completely melt it. heat (°c) for solid water is 2.10 j/g°c. hf = 334 j/g

Explanation:

Step1: Calculate the energy to raise the temperature of ice to \(0^{\circ}C\)

Use the formula \(Q_1 = mc\Delta T\), where \(m = 27.5g\), \(c=2.10J/g^{\circ}C\), \(\Delta T=0 - (- 8.0)=8.0^{\circ}C\)
\(Q_1=27.5g\times2.10J/g^{\circ}C\times8.0^{\circ}C\)
\(Q_1 = 27.5\times2.10\times8.0J\)
\(Q_1=462J\)

Step2: Calculate the energy to melt the ice at \(0^{\circ}C\)

Use the formula \(Q_2 = mH_f\), where \(m = 27.5g\) and \(H_f = 334J/g\)
\(Q_2=27.5g\times334J/g\)
\(Q_2 = 9185J\)

Step3: Calculate the total energy

\(Q = Q_1+Q_2\)
\(Q=462J + 9185J\)
\(Q = 9647J\)

Answer:

\(9647J\)