Question

how many total atoms of each element are present in the following formulas?
4 h₂o + 3 h₃po₄ + 2 p₄o₁₀
tap in the fields to enter the answers directly or tap on the number pad icon to use our built - in number pad.
hydrogen (h)
oxygen (o)
phosphorus (p)

Explanation:

Step1: Calculate the number of Hydrogen atoms

For \(4H_2O\), the number of \(H\) atoms is \(4\times2 = 8\). For \(3H_3PO_4\), the number of \(H\) atoms is \(3\times3=9\). There is no \(H\) in \(2P_4O_{10}\). So total \(H\) atoms: \(8 + 9=17\).

Step2: Calculate the number of Oxygen atoms

For \(4H_2O\), the number of \(O\) atoms is \(4\times1 = 4\). For \(3H_3PO_4\), the number of \(O\) atoms is \(3\times4 = 12\). For \(2P_4O_{10}\), the number of \(O\) atoms is \(2\times10=20\). So total \(O\) atoms: \(4+12 + 20=36\).

Step3: Calculate the number of Phosphorus atoms

There is no \(P\) in \(4H_2O\). For \(3H_3PO_4\), the number of \(P\) atoms is \(3\times1 = 3\). For \(2P_4O_{10}\), the number of \(P\) atoms is \(2\times4=8\). So total \(P\) atoms: \(3 + 8=11\).

Answer:

Hydrogen (\(H\)): \(17\)
Oxygen (\(O\)): \(36\)
Phosphorus (\(P\)): \(11\)