Question

1. how many moles of sulfur tetrafluoride are present in 2.62 grams of this compound? 2. how many grams of sulfur tetrafluoride are present in 2.67 moles of this compound? use the references to access important values if needed for this question.

Explanation:

Step1: Calculate molar mass of sulfur tetrafluoride ($SF_4$)

The molar mass of $S$ is approximately $32.07\ g/mol$ and the molar mass of $F$ is approximately $19.00\ g/mol$. For $SF_4$, the molar mass $M = 32.07+4\times19.00=32.07 + 76.00=108.07\ g/mol$.

Step2: Solve for moles in 2.62 grams

Use the formula $n=\frac{m}{M}$, where $m = 2.62\ g$ and $M = 108.07\ g/mol$. So $n=\frac{2.62}{108.07}\approx0.0242\ mol$.

Step3: Solve for grams in 2.67 moles

Use the formula $m=n\times M$, where $n = 2.67\ mol$ and $M = 108.07\ g/mol$. So $m=2.67\times108.07 = 2.67\times108.07=288.5469\approx289\ g$.

Answer:

1. $0.0242$ moles
2. $289$ grams