Question

how many moles of solute are contained in each solution? be sure each of your answer entries has the correct number of significant figures.
note: reference the si prefixes table for additional information.
part 1 of 2
665 ml of a 0.250 m hcl solution
mol solute
part 2 of 2
3.50 l of a 0.250 m hcl solution
mol solute

Explanation:

Step1: Recall the formula for moles ($n$)

The formula is $n = C\times V$, where $C$ is the molarity and $V$ is the volume in liters.

Step2: Convert volume for Part 1

Given $V = 665\ mL$. Convert to liters: $V=\frac{665}{1000}L = 0.665L$, $C = 0.250M$. Then $n=0.250\times0.665$.
$$n = 0.250\times0.665= 0.16625\approx0.166\ mol$$

Step3: Calculate for Part 2

Given $V = 3.50L$, $C = 0.250M$. Then $n=0.250\times3.50$.
$$n=0.250\times3.50 = 0.875\ mol$$

Answer:

Part 1: $0.166\ mol$
Part 2: $0.875\ mol$