Question

how many moles of propane react when 294 g of co₂ form? c₃h₈ + 5o₂ → 3co₂ + 4h₂o

Explanation:

Step1: Calculate moles of CO₂

The molar mass of \(CO_2\) is \(M = 12 + 2\times16=44\space g/mol\).
Using the formula \(n=\frac{m}{M}\), where \(m = 294\space g\) and \(M = 44\space g/mol\), we have \(n_{CO_2}=\frac{294}{44}\space mol\).

Step2: Use mole ratio from balanced equation

From the balanced equation \(C_3H_8 + 5O_2
ightarrow3CO_2 + 4H_2O\), the mole ratio of \(C_3H_8\) to \(CO_2\) is \(1:3\).
Let \(n_{C_3H_8}\) be the moles of propane. Then \(n_{C_3H_8}=\frac{1}{3}n_{CO_2}\).
Substitute \(n_{CO_2}=\frac{294}{44}\) into the equation: \(n_{C_3H_8}=\frac{1}{3}\times\frac{294}{44}=\frac{294}{132} = 2.23\space mol\) (rounded to two decimal places)

Answer:

\(2.23\space mol\)