Question

how many moles are present in 3.25×10²⁴ atoms p? 1.96×10⁴⁸ moles p 0.185 moles p 1.85 moles p 5.40 moles p

Explanation:

Step1: Recall Avogadro's number

Avogadro's number \( N_A=6.022\times 10^{23}\text{ atoms/mol}\)

Step2: Use the formula \(n = \frac{N}{N_A}\)

Given \(N = 3.25\times 10^{24}\text{ atoms}\), then \(n=\frac{3.25\times 10^{24}}{6.022\times 10^{23}}\)

$$n=\frac{3.25}{6.022}\times10^{24 - 23}$$

$$n\approx0.54\times10^{1}$$

$$n = 5.40\text{ mol}$$

Answer:

5.40 moles P