Question

1. how many molecules of carbon tetrachloride are present in 4.08 moles of this compound? 2. how many moles of carbon tetrachloride are present in 4.54x10^22 molecules of this compound? use the references to access important values if needed for this question. 9 more group attempts remaining. submit answer retry entire group

Explanation:

Step1: Recall Avogadro's number

Avogadro's number ($N_A$) is $6.022\times 10^{23}$ molecules/mol.

Step2: Solve for number of molecules in 4.08 moles

Use the formula $N = n\times N_A$, where $n = 4.08$ moles. So $N=4.08\times6.022\times 10^{23}$ molecules.
$N = 4.08\times6.022\times10^{23}=2.457\times 10^{24}$ molecules.

Step3: Solve for number of moles in $4.54\times 10^{22}$ molecules

Use the formula $n=\frac{N}{N_A}$, where $N = 4.54\times 10^{22}$ molecules. So $n=\frac{4.54\times 10^{22}}{6.022\times 10^{23}}$ moles.
$n=\frac{4.54\times 10^{22}}{6.022\times 10^{23}}= 0.0754$ moles.

Answer:

1. $2.457\times 10^{24}$ molecules
2. $0.0754$ moles