how many atoms of na are present in 1.15 moles of sodium? 6.92×10²¹ atoms na 9.11×10²⁵ atoms na 6.02×10²⁴ atoms na 6.92×10²³ atoms na

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Accepted Answer

# Explanation:
## Step1: Recall Avogadro's number
Avogadro's number $ N_A = 6.02\times10^{23}\text{ atoms/mol}$
## Step2: Use the formula $N = n\times N_A$
Given $n = 1.15\space mol$ of $Na$. Then $N=(1.15\space mol)\times(6.02\times 10^{23}\text{ atoms/mol})$
$$
\begin{align*}
N&=(1.15\times6.02)\times10^{23}\text{ atoms}\
& = 6.923\times10^{23}\text{ atoms}\approx6.92\times 10^{23}\text{ atoms}
\end{align*}
$$

# Answer:
$6.92\times 10^{23}\text{ atoms Na}$

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Question

Explanation:

Step1: Recall Avogadro's number

Step2: Use the formula \(N = n\times N_A\)

Answer: