Question

how many atoms of lithium (li) are present in the compound given the subscript and coefficient provided? 12 li₂aso₄ 15 8 36 3

Explanation:

Step1: Analyze sub - script and coefficient

The coefficient is 12, and the sub - script of Li in \(Li_3AsO_4\) is 3.

Step2: Calculate the number of Li atoms

The number of Li atoms \(N = \text{coefficient}\times\text{sub - script}\). So \(N=12\times3 = 36\).

Answer:

C. 36