how many al atoms are in 2.50 mol al?
1.51 x 10²⁴ atoms
2.41 x 10²³ atoms
9.03 x 10²² atoms
6.02 x 10²³ atoms

Question

Accepted Answer

# Explanation:
## Step1: Recall Avogadro's number
Avogadro's number $N_A = 6.02\times10^{23}\text{ atoms/mol}$
## Step2: Use the formula $N=n\times N_A$
Given $n = 2.50\text{ mol}$ of $Al$. Then $N=(2.50\text{ mol})\times(6.02\times 10^{23}\text{ atoms/mol})$
$$
\begin{align*}
N&=2.50\times6.02\times 10^{23}\text{ atoms}\
&=(2.50\times6.02)\times10^{23}\text{ atoms}\
& = 15.05\times10^{23}\text{ atoms}\
&=1.505\times 10^{24}\text{ atoms}\approx1.51\times 10^{24}\text{ atoms}
\end{align*}
$$

# Answer:
1.51 x 10²⁴ atoms

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Question

Explanation:

Step1: Recall Avogadro's number

Step2: Use the formula \(N=n\times N_A\)

Answer: