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Question
how does the following chemical equation support the law of conservation of matter?
$h_{2}+br_{2}\to2hbr$
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hydrogen and bromine are used on both sides of the equation.
the number of atoms on the reactant side is the same as the number of atoms on the product side.
the same type of matter is used on both the reactant and product sides.
each atom on the reactant side combines.
check answer remaining attempts : 3
The law of conservation of matter states that matter is neither created nor destroyed in a chemical reaction. This means the number of atoms of each element must be the same on both the reactant and product sides of a chemical equation.
- For hydrogen (\(H\)): On the reactant side, there are \(2\) atoms (\(H_2\)). On the product side, in \(2HBr\), there are \(2\times1 = 2\) hydrogen atoms.
- For bromine (\(Br\)): On the reactant side, there are \(2\) atoms (\(Br_2\)). On the product side, in \(2HBr\), there are \(2\times1= 2\) bromine atoms.
The first option is incorrect because just using elements on both sides is not the essence of the law (it's about atom - count conservation). The third option is wrong as the type of matter (substances) changes in a chemical reaction (reactants \(H_2\) and \(Br_2\) are different from product \(HBr\)). The fourth option is not relevant to the law of conservation of matter (the law is about atom - count, not about combination in general).
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The number of atoms on the reactant side is the same as the number of atoms on the product side.