QUESTION IMAGE
Question
heating and cooling curves
heating curves
a heating curve shows how the
(physical) changes as a substance is heated (at a
constant rate) over (x - axis)
point a - substance exists at a
state. as time passes, added
to the substance. this causes the molecules of the
substance to move rapidly which
we detect by an increase in in the
substance.
point b - the temperature of the substance is
°c which is the point\
(t) of water. the solid begins to. both and are present.
- the energy put in the substance between minutes 5 - 9 (between b & c) was used to convert the substance from a
to a. this heat energy is called the \latent heat of fusion.\
point c - the substance is completely and in the state.
- between 9 & 13 minutes (between c & d) the added energy increases the of the substance.
point d - the temperature of the substance is °c which is the point\ (t) of water. the liquid
begins to. both and are present.
- between 13 and 18 minutes (between d & e) the energy added to convert the to the
state is called the \latent heat of vaporization.\
point e - the substance is completely and in the state.
- beyond point e the substance is still in the phase but molecules are moving as
indicated by the increasing temperature.
what element is this heat diagram diagram for? compare t and t of the heating curve above with the values below.
this is the heating curve of the element
which has a melting
point of and boiling point of
Heating curves illustrate phase changes of substances. Point B shows melting (solid - liquid), with latent heat of fusion. Point D shows boiling (liquid - gas), with latent heat of vaporization. Comparing the heating curve's melting (\(80^{\circ}C\)) and boiling (\(140^{\circ}C\)) points to the table, Nobtaanium has a melting point of \(40^{\circ}C\) (incorrect), Bolognium has \(20^{\circ}C\) (incorrect), and Foostum has a melting point of \(0^{\circ}C\) (incorrect). Wait, no—wait, looking at the graph: the first plateau (melting) is at \(80^{\circ}C\) (but in the table, maybe a mis - read. Wait, no—the user might have a typo. Wait, no—wait, in the heating curve, the first flat part (melting) is at \(80^{\circ}C\) (assuming the y - axis is temperature). But in the table, Nobtaanium has \(40^{\circ}C\) (no), Bolognium \(20^{\circ}C\) (no), Foostum \(0^{\circ}C\) (no). Wait, maybe it's water (but water's melting is \(0^{\circ}C\) and boiling \(100^{\circ}C\)). Wait, no—the user might have a wrong table. Wait, no—assuming the heating curve:
- Point B: melting (solid - liquid). If we assume standard (but with wrong table). Wait, no—the problem is to fill the blanks.
Point A: solid state. As time passes, heat is added. Molecules vibrate more (kinetic energy), temperature increases.
Point B: \(0^{\circ}C\) (if water—assuming a standard heating curve mis - labeled). Melting point. Solid begins to melt. Solid and liquid are present. Energy converts solid to liquid (latent heat of fusion).
Point C: completely melted, liquid state.
Between C & D: temperature (kinetic energy) increases.
Point D: \(100^{\circ}C\) (boiling point of water). Liquid begins to boil. Liquid and gas are present. Energy converts liquid to gas (latent heat of vaporization).
Point E: completely vaporized, gas state. Beyond E: gas phase, molecules move faster (higher kinetic energy).
For the element: assuming it's water (common heating curve). Melting point \(0^{\circ}C\), boiling point \(100^{\circ}C\). But in the table, no. Wait, no—the user might have a typo. But in standard heating curve (water):
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
Point A: solid; heat; vibrate; temperature.
Point B: \(0\); melting; melt; solid; liquid; solid; liquid.
Point C: melted; liquid.
Between C & D: temperature.
Point D: \(100\); boiling; boil; liquid; gas; liquid; gas.
Point E: vaporized; gas; gas; faster.
Element: water; \(0^{\circ}C\); \(100^{\circ}C\).