Question

h2so4(aq) + lioh(aq) →
express your answer as a chemical equation. identify all of the phases in your answer.

Explanation:

Step1: Write the products of the acid - base reaction

Sulfuric acid \((H_2SO_4)\) reacts with lithium hydroxide \((LiOH)\) in an acid - base (neutralization) reaction. The general form of an acid - base reaction is \(H^+ + OH^-\to H_2O\). For the salt formation, the \(Li^+\) from \(LiOH\) and \(SO_4^{2 - }\) from \(H_2SO_4\) combine. Using the criss - cross method for charge balancing (\(Li^+\) and \(SO_4^{2 - }\)), the formula of the salt is \(Li_2SO_4\). The reaction is \(H_2SO_4(aq)+LiOH(aq)\to Li_2SO_4(aq)+H_2O(l)\).

Step2: Balance the chemical equation

For the hydrogen atoms: On the left - hand side, in \(H_2SO_4\) there are 2 \(H\) atoms and in \(LiOH\) there is 1 \(H\) atom. On the right - hand side, in \(H_2O\) there are 2 \(H\) atoms. For the lithium atoms: On the left - hand side, in \(LiOH\) there is 1 \(Li\) atom and on the right - hand side, in \(Li_2SO_4\) there are 2 \(Li\) atoms. For the sulfur atoms: There is 1 \(S\) atom on both sides. For the oxygen atoms: On the left - hand side, in \(H_2SO_4\) there are 4 \(O\) atoms and in \(LiOH\) there is 1 \(O\) atom. On the right - hand side, in \(Li_2SO_4\) there are 4 \(O\) atoms and in \(H_2O\) there is 1 \(O\) atom.
Multiply \(LiOH\) by 2. The balanced equation is \(H_2SO_4(aq)+2LiOH(aq)\to Li_2SO_4(aq)+2H_2O(l)\).

Answer:

\(H_2SO_4(aq)+2LiOH(aq)\to Li_2SO_4(aq)+2H_2O(l)\)