Question

given the same 12.50 g sample containing chlorine and oxygen, simplify the molar ratio of chlorine to oxygen in the imaginary 100.0 g sample by dividing the number of moles of each by the smallest of the two as shown in the table:

cl: 38.76% composition, 38.76 g mass of element in 100.0 grams of sample, 35.45 g/mol molar mass of element, 1.093 mol cl moles of element, 1.093 mol cl / 1.093 moles divided by smallest number of moles

o: 61.24% composition, 61.24 g mass of element in 100.0 grams of sample, 16.00 g/mol molar mass of element, 3.828 mol o moles of element, 3.828 mol o / 1.093 moles divided by smallest number of moles

cl:
choose
choose
1 mol cl
3.5 mol o
not enough information is given
o

Explanation:

Step1: Calculate the molar ratio of Cl

$$\frac{1.093\space mol\space Cl}{1.093}= 1\space mol\space Cl$$

Step2: Calculate the molar ratio of O

$$\frac{3.828\space mol\space O}{1.093}\approx3.5\space mol\space O$$

Answer:

Cl: \(1\space mol\space Cl\), O: \(3.5\space mol\space O\)