Question

given 3h₂ + n₂ → 2nh₃ if 2.0 mol of h₂ are consumed, how many mol of nh₃ form?

Explanation:

Step1: Determine the mole ratio

From the balanced equation \(3H_2 + N_2
ightarrow2NH_3\), the mole ratio of \(H_2\) to \(NH_3\) is \(3:2\).

Step2: Set up the proportion

Let \(x\) be the moles of \(NH_3\) formed. Using the mole ratio \(\frac{3\space mol\space H_2}{2\space mol\space NH_3}=\frac{2.0\space mol\space H_2}{x}\).
Cross - multiply: \(3x = 2\times2.0\).

Step3: Solve for \(x\)

\(x=\frac{2\times2.0}{3}=\frac{4}{3}\approx1.3\space mol\)

Answer:

\(1.3\space mol\)