Question

give the n and i values for the following orbitals: 6s

Explanation:

Step1: Recall the principal quantum number ($n$)

The principal quantum number $n$ represents the energy level or shell. For the orbital $6s$, the number before the orbital type ($s$) is the value of $n$. So, $n = 6$.

Step2: Recall the azimuthal quantum number ($l$)

The azimuthal quantum number $l$ has values based on the orbital type:

• For $s$ - orbital: $l=0$
• For $p$ - orbital: $l = 1$
• For $d$ - orbital: $l=2$
• For $f$ - orbital: $l = 3$

Since the orbital is $s$, $l = 0$.

Answer:

$n = 6$, $l=0$ (the fourth option: $n = 6, l = 0$)