QUESTION IMAGE
Question
- give the oxidation number for each element in the following:
a) \\(\text{cl}_2\\)
b) \\(\text{hno}_3\\)
c) \\(\text{kmno}_4\\)
d) \\(\text{no}_3^{-1}\\)
e) \\(\text{h}_2\text{so}_4\\)
f) \\(\text{nh}_4^{+1}\\)
Identify rules for oxidation states
We apply standard rules to assign oxidation numbers:
- Free elements in their molecular state have an oxidation number of \(0\).
- Hydrogen is typically \(+1\) when bonded to nonmetals.
- Oxygen is typically \(-2\) in most compounds.
- Group 1 alkali metals (like \(\text{K}\)) always have an oxidation number of \(+1\).
- The sum of oxidation numbers in a neutral compound is \(0\), and in a polyatomic ion, it equals the ion's charge.
Determine oxidation numbers for a, b, and c
- For a) \(\text{Cl}_2\):
This is a pure elemental form.
- For b) \(\text{HNO}_3\):
Hydrogen is \(+1\), oxygen is \(-2\).
- For c) \(\text{KMnO}_4\):
Potassium is \(+1\), oxygen is \(-2\).
Determine oxidation numbers for d, e, and f
- For d) \(\text{NO}_3^{-1}\):
Oxygen is \(-2\). The sum equals the charge \(-1\).
- For e) \(\text{H}_2\text{SO}_4\):
Hydrogen is \(+1\), oxygen is \(-2\).
- For f) \(\text{NH}_4^{+1}\):
Hydrogen is \(+1\). The sum equals the charge \(+1\).
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Question 7
a) \(\text{Cl}_2\):
- \(\text{Cl} = 0\)
b) \(\text{HNO}_3\):
- \(\text{H} = +1\)
- \(\text{N} = +5\)
- \(\text{O} = -2\)
c) \(\text{KMnO}_4\):
- \(\text{K} = +1\)
- \(\text{Mn} = +7\)
- \(\text{O} = -2\)
d) \(\text{NO}_3^{-1}\):
- \(\text{N} = +5\)
- \(\text{O} = -2\)
e) \(\text{H}_2\text{SO}_4\):
- \(\text{H} = +1\)
- \(\text{S} = +6\)
- \(\text{O} = -2\)
f) \(\text{NH}_4^{+1}\):
- \(\text{N} = -3\)
- \(\text{H} = +1\)