Question

gaseous ammonia chemically reacts with oxygen (o₂) gas to produce nitrogen monoxide gas and water vapor. calculate the moles of water produced by the reaction of 0.10 mol of oxygen. be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

Explanation:

Step1: Write the balanced chemical equation

$$4NH_3 + 5O_2 ightarrow4NO + 6H_2O$$

Step2: Determine the mole ratio

From the balanced equation, the mole ratio of \(O_2\) to \(H_2O\) is \(5:6\).

Step3: Calculate the moles of water

Let \(n\) be the moles of \(H_2O\). Using the mole ratio \(\frac{n}{0.10}=\frac{6}{5}\). Solving for \(n\), we get \(n = 0.10\times\frac{6}{5}\).
$$n=0.12$$

Answer:

\(0.12\space mol\)