Question

a gas with an unknown volume is originally 588 k. when the volume of the gas changes to 852 ml, the temperature changes to 725 k. what is the initial volume of the gas? v = ? ml assume that the number of moles and the pressure remain constant.

Explanation:

Step1: Recall Charles's Law formula

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$ (constant n, P)

Step2: Identify known values

$T_1=588\ \text{K}, T_2=725\ \text{K}, V_2=852\ \text{mL}, V_1=?$

Step3: Rearrange formula for $V_1$

$V_1 = V_2 \times \frac{T_1}{T_2}$

Step4: Calculate $V_1$

$V_1 = 852 \times \frac{588}{725} \approx 688$

Answer:

688 mL