Question

gas stoichiometry at stp

caco₃(s) x07a cao(s) + co₂(g)
3.25 mol caco₃ decomposes according to the reaction above.
what volume of co₂ gas is produced once the gas cools to
stp?
l co₂

Explanation:

Step1: Find mole ratio of CO₂ to CaCO₃

From reaction: 1 mol CaCO₃ → 1 mol CO₂, so mole ratio = 1:1.
Moles of CO₂ = 3.25 mol.

Step2: Calculate volume at STP

1 mol gas at STP = 22.4 L.
Volume = 3.25 mol × 22.4 L/mol = 72.8 L.

Answer:

72.8