Question

the freezing point of water is 32° f. tim added potassium and found out that the freezing point went down by 8° f. what was the freezing point of the water with the added potassium?

Explanation:

Step1: Subtract the decrease from the original freezing point

The original freezing point is \(32^{\circ}F\) and it decreased by \(8^{\circ}F\). So we calculate \(32 - 8\).

$$32-8=(20 + 12)-8=20+(12 - 8)=20 + 4$$

Answer:

\(24^{\circ}F\)