Question

formulas for ionic compounds with monatomic ions only
using each of the following pairs of ions, construct the chemic
ions in the space provided.

1. au³+ f¹-

formula:
ratio

Explanation:

Step1: Determine the charge balance

For an ionic compound, the total positive charge must equal the total negative charge. The gold ion \(Au^{3 +}\) has a charge of \(+ 3\), and the fluoride ion \(F^{-}\) has a charge of \(-1\).
Let the number of \(Au^{3+}\) ions be \(x\) and the number of \(F^{-}\) ions be \(y\). We need \(3x-y = 0\). If \(x = 1\), then \(y=3\)

Step2: Write the formula

The chemical formula of an ionic compound is written with the cation first and then the anion. So, for \(x = 1\) \(Au^{3+}\) and \(y = 3\) \(F^{-}\) ions, the formula is \(AuF_{3}\)

Step3: Determine the ratio

The ratio of \(Au^{3+}\) to \(F^{-}\) ions is based on the sub - scripts in the formula. The sub - script of \(Au\) is \(1\) and the sub - script of \(F\) is \(3\). So the ratio of \(Au^{3+}:F^{-}\) is \(1:3\)

Answer:

formula: \(AuF_{3}\)
ratio: \(1:3\)