Question

a flexible container holding 1.25 moles of a gas contracts from 25.0 l to 10.0 l when some gas is removed. the pressure and temperature remain the same throughout. how many moles of gas are in the contracted container? n₂ = ? mol

Explanation:

Step1: Apply Avogadro's Law

$\frac{V_1}{n_1} = \frac{V_2}{n_2}$

Step2: Rearrange for $n_2$

$n_2 = n_1 \times \frac{V_2}{V_1}$

Step3: Substitute values

$n_2 = 1.25\ \text{mol} \times \frac{10.0\ \text{L}}{25.0\ \text{L}}$

Step4: Calculate result

$n_2 = 1.25 \times 0.4 = 0.500\ \text{mol}$

Answer:

0.500 mol