Question

a flexible container holding 4.00 moles of a gas contracts from 89.6 l to 44.8 l when some gas is released. pressure and temperature remain constant throughout. how many moles of gas are in the reduced container? n₂ = ? mol

Explanation:

Step1: Apply Avogadro's Law

$\frac{V_1}{n_1} = \frac{V_2}{n_2}$ (P, T constant)

Step2: Rearrange for $n_2$

$n_2 = n_1 \times \frac{V_2}{V_1}$

Step3: Substitute values

$n_2 = 4.00\ \text{mol} \times \frac{44.8\ \text{L}}{89.6\ \text{L}} = 2.00\ \text{mol}$

Answer:

2.00