Question

1. a fixed amount of gas at 25.0°c occupies a volume of 10.0 l when the pressure is 629 torr. use charless law to calculate the volume (in l) the gas will occupy when the temperature is increased to 121°c while maintaining the pressure at 629 torr. a. 10.9 l b. 13.2 l c. 2.07 l d. 7.56 l e. 48.4 l

Explanation:

Step1: Convert temperatures to Kelvin

Charles's law requires temperature in Kelvin.
$T_1 = 25.0 + 273.15=298.15\ K$
$T_2 = 121+ 273.15 = 394.15\ K$

Step2: Apply Charles's law formula

Charles's law is $\frac{V_1}{T_1}=\frac{V_2}{T_2}$. We know $V_1 = 10.0\ L$, $T_1 = 298.15\ K$, $T_2 = 394.15\ K$.
Solve for $V_2$: $V_2=\frac{V_1\times T_2}{T_1}$
Substitute the values: $V_2=\frac{10.0\times394.15}{298.15}$
$V_2=\frac{3941.5}{298.15}\approx13.2\ L$

Answer:

B. 13.2 L