Question

find the value of x in the isosceles triangle shown below. choose 1 answer. x = √20

Explanation:

Step1: Apply Pythagorean theorem

Let's consider the right - triangle formed. If we assume the base of the isosceles triangle is divided into two equal parts. Let the height of the isosceles triangle be $h$ and half of the base be $b$. Here, we can use the Pythagorean theorem $a^{2}+b^{2}=c^{2}$. In the right - triangle with sides $h = 4$, $b = 2$ and hypotenuse $x$.
$x=\sqrt{4^{2}+2^{2}}$

Step2: Calculate the value of $x$

$x=\sqrt{16 + 4}=\sqrt{20}$

Answer:

$x = \sqrt{20}$