Question

fill in the summary chart and turn in when done identifying types of reactions by matter balance each of the following reactions and identify each type of reaction by matter. 1. \text{nabr} + \text{ca(oh)}_2 \
ightarrow \text{cabr}_2 + \text{naoh} click to add text

Explanation:

Step1: Identify Reaction Type

The reaction is \( \text{NaBr} + \text{Ca(OH)}_2
ightarrow \text{CaBr}_2 + \text{NaOH} \). This is a double - displacement reaction (ions swap: \( \text{Na}^+ \) with \( \text{Ca}^{2+} \), \( \text{Br}^- \) with \( \text{OH}^- \)).

Step2: Balance the Equation

1. List the number of each atom on both sides:

• Left: \( \text{Na}: 1 \), \( \text{Br}: 1 \), \( \text{Ca}: 1 \), \( \text{O}: 2 \), \( \text{H}: 2 \)
• Right: \( \text{Na}: 1 \), \( \text{Br}: 2 \), \( \text{Ca}: 1 \), \( \text{O}: 1 \), \( \text{H}: 1 \)

1. Balance \( \text{NaBr} \) and \( \text{NaOH} \) first. Let's start with \( \text{NaBr} \). To balance \( \text{Br} \), put a coefficient of 2 in front of \( \text{NaBr} \): \( 2\text{NaBr} + \text{Ca(OH)}_2

ightarrow \text{CaBr}_2 + \text{NaOH} \)

1. Now balance \( \text{Na} \) and \( \text{OH}^- \). Since we have 2 \( \text{Na} \) on the left, put a coefficient of 2 in front of \( \text{NaOH} \): \( 2\text{NaBr} + \text{Ca(OH)}_2

ightarrow \text{CaBr}_2 + 2\text{NaOH} \)

1. Check the atoms:

• Left: \( \text{Na}: 2 \), \( \text{Br}: 2 \), \( \text{Ca}: 1 \), \( \text{O}: 2 \), \( \text{H}: 2 \)
• Right: \( \text{Na}: 2 \), \( \text{Br}: 2 \), \( \text{Ca}: 1 \), \( \text{O}: 2 \), \( \text{H}: 2 \) (balanced)

Answer:

The balanced equation is \( 2\text{NaBr} + \text{Ca(OH)}_2=\text{CaBr}_2 + 2\text{NaOH} \) and the reaction type is double - displacement reaction.