Question

fill out the table below based on the following chemical equation: rb + s → rb₂s the correct coefficients for the equation is: rb + s → rb₂s

Explanation:

Step1: Balance the chemical equation

The un - balanced equation is \(Rb + S_8
ightarrow Rb_2S\).
For sulfur (\(S\)): In \(S_8\), the number of \(S\) atoms is \(8\). In \(Rb_2S\), the number of \(S\) atoms is \(1\). To balance \(S\), we put a coefficient of \(8\) in front of \(Rb_2S\). So the equation becomes \(Rb+S_8
ightarrow8Rb_2S\).
For rubidium (\(Rb\)): In \(8Rb_2S\), the number of \(Rb\) atoms is \(16\). So we put a coefficient of \(16\) in front of \(Rb\). The balanced equation is \(16Rb + S_8
ightarrow8Rb_2S\).

Step2: Calculate the total number of atoms before (reactants)

• For \(Rb\): The coefficient of \(Rb\) is \(16\), so the number of \(Rb\) atoms is \(16\).
• For \(S\): The coefficient of \(S_8\) is \(1\), and in \(S_8\) the number of \(S\) atoms is \(8\).

Step3: Calculate the total number of atoms after (products)

• For \(Rb\): The coefficient of \(Rb_2S\) is \(8\), and in \(Rb_2S\) the number of \(Rb\) atoms per formula unit is \(2\). So the total number of \(Rb\) atoms is \(8\times2=16\).
• For \(S\): The coefficient of \(Rb_2S\) is \(8\), and in \(Rb_2S\) the number of \(S\) atoms per formula unit is \(1\). So the total number of \(S\) atoms is \(8\times1 = 8\).

Answer:

The balanced equation is \(16Rb+S_8
ightarrow8Rb_2S\).

• Total # Before (reactants):
• \(Rb\): \(16\)
• \(S\): \(8\)
• Total # After (Products):
• \(Rb\): \(16\)
• \(S\): \(8\)