Question

fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table.
some ionic compounds
cation | anion | empirical formula | name of compound
cr²⁺ | cn⁻ | |
ca²⁺ | so₄²⁻ | |
pb⁴⁺ | c₂h₃o₂⁻ | |

Explanation:

First Row (Cation: $\boldsymbol{\ce{Cr^{2+}}}$, Anion: $\boldsymbol{\ce{CN^-}}$)

Step1: Balance charges. $\ce{Cr^{2+}}$ (charge +2) and $\ce{CN^-}$ (charge -1). To balance, need 2 $\ce{CN^-}$ for 1 $\ce{Cr^{2+}}$.

Empirical formula: $\ce{Cr(CN)2}$

Step2: Name the compound. Cation is chromium(II), anion is cyanide.

Name: Chromium(II) cyanide

Second Row (Cation: $\boldsymbol{\ce{Ca^{2+}}}$, Anion: $\boldsymbol{\ce{SO4^{2-}}}$)

Step1: Balance charges. $\ce{Ca^{2+}}$ (charge +2) and $\ce{SO4^{2-}}$ (charge -2). 1:1 ratio.

Empirical formula: $\ce{CaSO4}$

Step2: Name the compound. Cation is calcium, anion is sulfate.

Name: Calcium sulfate

Third Row (Cation: $\boldsymbol{\ce{Pb^{4+}}}$, Anion: $\boldsymbol{\ce{C2H3O2^-}}$)

Step1: Balance charges. $\ce{Pb^{4+}}$ (charge +4) and $\ce{C2H3O2^-}$ (charge -1). Need 4 $\ce{C2H3O2^-}$ for 1 $\ce{Pb^{4+}}$.

Empirical formula: $\ce{Pb(C2H3O2)4}$

Step2: Name the compound. Cation is lead(IV), anion is acetate.

Name: Lead(IV) acetate

Answer:

cation	anion	empirical formula	name of compound
$\ce{Ca^{2+}}$	$\ce{SO4^{2-}}$	$\ce{CaSO4}$	Calcium sulfate
$\ce{Pb^{4+}}$	$\ce{C2H3O2^-}$	$\ce{Pb(C2H3O2)4}$	Lead(IV) acetate