Question

is this equation balanced or unbalanced? 2fe₂o₃ + 3c → 4fe + 3co₂

Explanation:

Step1: Count atoms on reactant side

• For Fe: \(2\times2 = 4\) (from \(2Fe_2O_3\))
• For O: \(2\times3=6\) (from \(2Fe_2O_3\))
• For C: \(3\) (from \(3C\))

Step2: Count atoms on product side

• For Fe: \(4\) (from \(4Fe\))
• For O: \(3\times2 = 6\) (from \(3CO_2\))
• For C: \(3\) (from \(3CO_2\))

Since the number of Fe, O, and C atoms is the same on both sides of the equation \(2Fe_2O_3+3C = 4Fe + 3CO_2\)

Answer:

balanced