Question

enter the units of the students answer.
\\( \frac { ( 0.36 \mathrm { l } ) \left( \frac { 1 \mathrm { ml } } { 10 ^ { - 3 } \mathrm { l } } \
ight) \left( 1.24 \frac { \mathrm { g } } { \mathrm { ml } } \
ight) } { \left( 58.45 \frac { \mathrm { g } } { \mathrm { mol } } \
ight) } = ? \frac { \mathrm { l } } { \mathrm { mol } } \\)

Explanation:

Step1: Analyze the units of each term

• The first term has unit \(L\).
• The second term \(\frac{1\mathrm{mL}}{10^{- 3}\mathrm{L}}\) has unit \(\frac{\mathrm{mL}}{\mathrm{L}}\).
• The third term \(1.24\frac{\mathrm{g}}{\mathrm{mL}}\) has unit \(\frac{\mathrm{g}}{\mathrm{mL}}\).
• The fourth term \(58.45\frac{\mathrm{g}}{\mathrm{mol}}\) has unit \(\frac{\mathrm{g}}{\mathrm{mol}}\).

Step2: Cancel out the units

$$
LATEXBLOCK0
$$

Answer:

\(\mathrm{mol}\)