Question

electron configuration (level 4)
give the electron configuration for tellurium (te).
you must use the noble gas configuration (the shortcut)
kr 4s²
valence electrons

Explanation:

Step1: Locate tellurium in periodic table

Tellurium (Te) has atomic number 52.

Step2: Determine noble - gas core

The noble gas before Te with the closest lower atomic number is krypton (Kr) with atomic number 36. So, we start with [Kr].

Step3: Fill remaining electrons

After [Kr], we need to account for 52 - 36=16 more electrons. The electron - filling order is $5s$, $4d$, $5p$. First, 2 electrons go into the $5s$ orbital ($5s^{2}$), then 10 electrons go into the $4d$ orbital ($4d^{10}$), and finally 4 electrons go into the $5p$ orbital ($5p^{4}$).

Answer:

$[Kr]5s^{2}4d^{10}5p^{4}$