for each reaction, write the chemical formulae of the oxidized reactants in the space provided. write the chemical formulae of the reduced reactants in the space provided.
ca(s) + zncl₂(aq) → zn(s) + cacl₂(aq)
reactants oxidized:
reactants reduced:
zn(s) + 2agno₃(aq) → zn(no₃)₂(aq) + 2ag(s)
reactants oxidized:
reactants reduced:
2agno₃(aq) + cu(s) → 2ag(s) + cu(no₃)₂(aq)
reactants oxidized:
reactants reduced:

Question

Accepted Answer

# Explanation:
## Step1: Determine oxidation states
Oxidation state of $Ca$ in $Ca(s)$ is $0$, in $CaCl_2$ is $+2$. Oxidation state of $Zn$ in $ZnCl_2$ is $+2$, in $Zn(s)$ is $0$.
Oxidation state of $Zn$ in $Zn(s)$ is $0$, in $Zn(NO_3)_2$ is $+2$. Oxidation state of $Ag$ in $AgNO_3$ is $+1$, in $Ag(s)$ is $0$.
Oxidation state of $Cu$ in $Cu(s)$ is $0$, in $Cu(NO_3)_2$ is $+2$. Oxidation state of $Ag$ in $AgNO_3$ is $+1$, in $Ag(s)$ is $0$.
## Step2: Identify oxidized and reduced reactants
Substance that undergoes increase in oxidation state is oxidized. Substance that undergoes decrease in oxidation state is reduced.
For $Ca(s)+ZnCl_2(aq)\to Zn(s)+CaCl_2(aq)$: $Ca$ is oxidized ($0\to + 2$), $Zn^{2 +}$ (from $ZnCl_2$) is reduced ($+2\to0$).
For $Zn(s)+2AgNO_3(aq)\to Zn(NO_3)_2(aq)+2Ag(s)$: $Zn$ is oxidized ($0\to + 2$), $Ag^{+}$ (from $AgNO_3$) is reduced ($+1\to0$).
For $2AgNO_3(aq)+Cu(s)\to2Ag(s)+Cu(NO_3)_2(aq)$: $Cu$ is oxidized ($0\to + 2$), $Ag^{+}$ (from $AgNO_3$) is reduced ($+1\to0$).

# Answer:
- For $Ca(s)+ZnCl_2(aq)\to Zn(s)+CaCl_2(aq)$:
    - reactants oxidized: $Ca$
    - reactants reduced: $ZnCl_2$
 - For $Zn(s)+2AgNO_3(aq)\to Zn(NO_3)_2(aq)+2Ag(s)$:
    - reactants oxidized: $Zn$
    - reactants reduced: $AgNO_3$
 - For $2AgNO_3(aq)+Cu(s)\to2Ag(s)+Cu(NO_3)_2(aq)$:
    - reactants oxidized: $Cu$
    - reactants reduced: $AgNO_3$

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QUESTION IMAGE

Question

Explanation:

Step1: Determine oxidation states

Step2: Identify oxidized and reduced reactants

Answer: