Question

draw the lewis structure for a iodide monochloride (icl) molecule.

Explanation:

1. Count total valence electrons: I (7) + Cl (7) = 14.
2. Connect I and Cl with a single bond (2 electrons used, 12 left).
3. Distribute remaining electrons as lone pairs: 6 on each atom (3 lone pairs each) to satisfy octets.

Answer:

The Lewis structure of ICl is:
:$\ddot{\text{I}}-\ddot{\text{Cl}}$:
(Each atom has 3 lone pairs and shares 1 bond pair.)