Question

1. a) draw a bohr rutherford diagram of a magnesium ion, beryllium ion. state the ionic charge!!! (ex -2, +3 etc)

Explanation:

Step1: Determine the atomic number of magnesium

Magnesium (Mg) has an atomic number of 12. So, it has 12 protons and in a neutral atom, 12 electrons.

Step2: Consider the ion - formation

Magnesium forms a cation by losing 2 electrons to achieve a stable noble - gas electron configuration. So, a magnesium ion ($Mg^{2 + }$) has 10 electrons.

Step3: Draw the Bohr - Rutherford diagram

The nucleus contains 12 protons and some neutrons (usually 12 neutrons for the most common isotope). The first electron shell can hold 2 electrons and the second shell can hold 8 electrons. So, for $Mg^{2+}$, there are 2 electrons in the first shell and 8 electrons in the second shell.

Answer:

The Bohr - Rutherford diagram of a magnesium ion ($Mg^{2+}$) has a nucleus with 12 protons and some neutrons, 2 electrons in the first shell and 8 electrons in the second shell. The ionic charge is + 2.