Question

1. the double replacement reaction is between aqueous lead(ll) nitrate and potassium iodide: pb(no₃)₂ + ki →? identify the possible products of this reaction. i need a hint select all that apply: pbk k(no₃)₂ kno₃ pbi pbi₂ (no₃)₂i

Explanation:

Step1: Recall double replacement rules

In a double replacement reaction, cations and anions swap. Reactants: \( \text{Pb(NO}_3\text{)}_2 \) (cations: \( \text{Pb}^{2+} \), anions: \( \text{NO}_3^- \)) and \( \text{KI} \) (cations: \( \text{K}^+ \), anions: \( \text{I}^- \)).

Step2: Swap cations/anions

New combinations: \( \text{Pb}^{2+} \) with \( \text{I}^- \), \( \text{K}^+ \) with \( \text{NO}_3^- \).

Step3: Determine formulas

• For \( \text{Pb}^{2+} \) and \( \text{I}^- \): Charge balance: \( 2(1^-) = 2^+ \), so \( \text{PbI}_2 \).
• For \( \text{K}^+ \) and \( \text{NO}_3^- \): Charge balance: \( 1^+ + 1^- = 0 \), so \( \text{KNO}_3 \).

Answer:

\( \text{KNO}_3 \), \( \text{PbI}_2 \) (select the checkboxes for \( \text{KNO}_3 \) and \( \text{PbI}_2 \))