Question

double displacement reactions
a precipitation reaction occurs when two solutions are mixed and an insoluble product is formed. solubility is the ability of a substance to dissolve in water and the solubility rules will allow you to predict whether a substance is soluble. looking at the reactants given in each we can see that the compounds are soluble by the (aq) written beside them. if a product is soluble you should indicate that with the (aq) symbol. an insoluble product is a precipitate and is denoted with the (s) symbol representing solid. first predict the possible products of the following reactions ensuring that the formulas are correct based on the charge of the cation and anion, then include state of matter and finally balance using coefficients.

1. ( mathrm{li}_{2} mathrm{~s}_{(mathrm{aq})}+mathrm{agno}_{3(mathrm{aq})} \to )
2. ( mathrm{bacl}_{2(mathrm{aq})}+mathrm{na}_{2} mathrm{co}_{3(mathrm{aq})} \to )
3. ( mathrm{alcl}_{3(mathrm{aq})}+mathrm{na}_{3} mathrm{po}_{4(mathrm{aq})} \to )
4. ( mathrm{ba}left(mathrm{no}_{3}

ight)_{2(mathrm{aq})}+mathrm{h}_{2} mathrm{so}_{4(mathrm{aq})} \to )

1. ( mathrm{k}_{2} mathrm{so}_{4(mathrm{aq})}+mathrm{caf}_{2(mathrm{aq})} \to )
2. ( mathrm{kcl}_{(mathrm{aq})}+mathrm{bano} 3_{(mathrm{aq})} \to )
3. ( mathrm{k}_{3} mathrm{po}_{4(mathrm{aq})}+left(mathrm{nh}_{4}

ight) mathrm{i}_{(mathrm{aq})} \to )

1. ( mathrm{li}_{3}left(mathrm{po}_{4}

ight)_{(mathrm{aq})}+mathrm{bacl}_{2(mathrm{aq})} \to )

1. ( mathrm{albr}_{3(mathrm{aq})}+mathrm{k}_{3} mathrm{po}_{4(mathrm{aq})} \to )
2. ( mathrm{zn}left(mathrm{no}_{3}

ight)_{2(mathrm{aq})}+mathrm{ba}(mathrm{oh})_{2(mathrm{aq})} \to )

Explanation:

Step1: Write the general form of double - displacement reaction

For two ionic compounds \(AB\) and \(CD\), the double - displacement reaction is \(AB+CD
ightarrow AD + CB\)

Step2: Predict the products for each reaction

• Reaction 1:

\(Li_2S(aq)+AgNO_3(aq)
ightarrow LiNO_3(aq)+Ag_2S(s)\)
Balanced equation: \(Li_2S(aq)+2AgNO_3(aq)
ightarrow 2LiNO_3(aq)+Ag_2S(s)\)

• Reaction 2:

\(BaCl_2(aq)+Na_2CO_3(aq)
ightarrow BaCO_3(s)+2NaCl(aq)\)

• Reaction 3:

\(AlCl_3(aq)+Na_3PO_4(aq)
ightarrow AlPO_4(s)+3NaCl(aq)\)

• Reaction 4:

\(Ba(NO_3)_2(aq)+H_2SO_4(aq)
ightarrow BaSO_4(s)+2HNO_3(aq)\)

• Reaction 5:

\(K_2SO_4(aq)+CaF_2(aq)
ightarrow 2KF(aq)+CaSO_4(s)\)

• Reaction 6:

\(KCl(aq)+Ba(NO_3)_2(aq)
ightarrow BaCl_2(aq)+KNO_3(aq)\) (No precipitate forms as both products are soluble)

• Reaction 7:

\(K_3PO_4(aq)+(NH_4)I(aq)
ightarrow KI(aq)+(NH_4)_3PO_4(aq)\) (No precipitate forms as both products are soluble)

• Reaction 8:

\(Li_3PO_4(aq)+BaCl_2(aq)
ightarrow Ba_3(PO_4)_2(s)+6LiCl(aq)\)
Balanced equation: \(2Li_3PO_4(aq)+3BaCl_2(aq)
ightarrow Ba_3(PO_4)_2(s)+6LiCl(aq)\)

• Reaction 9:

\(AlBr_3(aq)+K_3PO_4(aq)
ightarrow AlPO_4(s)+3KBr(aq)\)

• Reaction 10:

\(Zn(NO_3)_2(aq)+Ba(OH)_2(aq)
ightarrow Zn(OH)_2(s)+Ba(NO_3)_2(aq)\)

Answer:

1. \(Li_2S(aq)+2AgNO_3(aq)

ightarrow 2LiNO_3(aq)+Ag_2S(s)\)

1. \(BaCl_2(aq)+Na_2CO_3(aq)

ightarrow BaCO_3(s)+2NaCl(aq)\)

1. \(AlCl_3(aq)+Na_3PO_4(aq)

ightarrow AlPO_4(s)+3NaCl(aq)\)

1. \(Ba(NO_3)_2(aq)+H_2SO_4(aq)

ightarrow BaSO_4(s)+2HNO_3(aq)\)

1. \(K_2SO_4(aq)+CaF_2(aq)

ightarrow 2KF(aq)+CaSO_4(s)\)

1. \(KCl(aq)+Ba(NO_3)_2(aq)

ightarrow BaCl_2(aq)+KNO_3(aq)\) (No reaction as no precipitate)

1. \(K_3PO_4(aq)+(NH_4)I(aq)

ightarrow KI(aq)+(NH_4)_3PO_4(aq)\) (No reaction as no precipitate)

1. \(2Li_3PO_4(aq)+3BaCl_2(aq)

ightarrow Ba_3(PO_4)_2(s)+6LiCl(aq)\)

1. \(AlBr_3(aq)+K_3PO_4(aq)

ightarrow AlPO_4(s)+3KBr(aq)\)

1. \(Zn(NO_3)_2(aq)+Ba(OH)_2(aq)

ightarrow Zn(OH)_2(s)+Ba(NO_3)_2(aq)\)