Question

directions: for the three elements below, fill in the missing information for each element: identify the atomic number, mass, and the number of protons, neutrons, and electrons.

atomic # = 8
atomic mass = 15.999

of protons =

of neutrons =

of electrons =

atomic # = 30
atomic mass = 65.39

of protons =

of neutrons =

of electrons =

atomic # = 3
atomic mass = 6.941

of protons =

of neutrons =

of electrons =

Explanation:

Step1: Determine atomic number, protons, electrons for each element

• For oxygen (\(O\)): The atomic number (\(Z\)) is given as \(8\). In a neutral atom, the number of protons (\(\#\) of Protons) = atomic number = \(8\), and the number of electrons (\(\#\) of Electrons) = number of protons = \(8\).
• For zinc (\(Zn\)): The atomic number (\(Z\)) is \(30\). So, \(\#\) of Protons=\(30\), \(\#\) of Electrons=\(30\).
• For lithium (\(Li\)): The atomic number (\(Z\)) is \(3\). Thus, \(\#\) of Protons=\(3\), \(\#\) of Electrons=\(3\).

Step2: Calculate number of neutrons for each element

• For oxygen:

The atomic mass (\(A\)) is \(15.999\approx16\). Using the formula \(A = Z + N\) (where \(N\) is the number of neutrons), we get \(N=A - Z\). So, \(N = 16-8=8\).

• For zinc:

The atomic mass (\(A\)) is \(65.39\approx65\). Using \(A = Z + N\), we have \(N=65 - 30=35\).

• For lithium:

The atomic mass (\(A\)) is \(6.941\approx7\). Using \(A = Z + N\), we obtain \(N=7 - 3=4\).

Answer:

Element	Atomic \# (\(Z\))	\(\#\) of Protons	\(\#\) of Electrons	\(\#\) of Neutrons	Atomic Mass (\(A\))
\(Zn\)	\(30\)	\(30\)	\(30\)	\(35\)	\(65.39\approx65\)
\(Li\)	\(3\)	\(3\)	\(3\)	\(4\)	\(6.941\approx7\)