Question

determine the number of particles in the 0.28 mol sample of babr₂.
1 mol babr₂ = 6.02 × 10²³ particles babr₂
0.28 mol babr₂ = ? × 10? particles babr₂
enter the coefficient in the green box and the exponent in the yellow box.
round your coefficient to two decimal places.

Explanation:

Step1: Set up the conversion

Use the conversion factor \(1\space mol = 6.02\times10^{23}\space particles\).
For \(0.28\space mol\) of \(BaBr_2\), the number of particles \(N\) is \(N=0.28\times6.02\times 10^{23}\).

Step2: Calculate the coefficient

\(0.28\times6.02 = 1.6856\approx1.69\) (rounded to two decimal places).
The exponent of \(10\) remains \(23\) since we are just multiplying the coefficient part (\(0.28\times6.02\)) and keeping the power - of - ten notation.

Answer:

Coefficient: \(1.69\), Exponent: \(23\)